Hi, I'm just learning about async/await, and more generally, callbacks/promises. You do not return anything from your openChat function, so that function resolves to undefined. Get async: false. The problem is that I don't know why my async function doesn't return I'm doing requests to my API server to authenticate a user, that's not the problem. WRITTEN BY Prashanth Krishnamurthy Technologist | Creator of Things js undici fetch data async. The string is correctly displayed the console.log of the async function). What does "async: false" do in jQuery.ajax()?, JQuery Ajax, async : false, return undefined, Avoiding async: false; in jQuery AJAX within a function, How to avoid ajax async when using jQuery events async function checksubsdetails() { // Promisify the `db_office.query` function (depending on the library, // it may already have a promisified . javascript make async get request. I can't get a callback to pass its return value correctly in an async function (I've been grinding through async learning recently). async function printThis(statement) { console.log(statement); return true; } const ret = printThis("hello world").then(ret => console.log(ret)); /* output hello world true */ Also see Function has will either specified return or undefined Stay in touch! Async return values. I am having a problem when I return a Boolean value from the code into another function. but I am unable to store that value in a local variable in the . The function should return a string depending on a single input param. How to return value of variable from async JS function in React Native; Can't return value inside Async Function; My javascript Async Await api request returns a strange object 1 yr. ago. You just need to add return true; after splicing the element. The feature is for a 1-1 user chat. This is using a REST endpoint to pull data, the console.logs do show the data is correct, however return comes back as undefined 4 1 this.allPeople.forEach(async person => { 2 const dodString = await this.getRelatedRecords(person); //undefined 3 } 4 This is the main function that returns a promise / data 22 1 async getRelatedRecords(person) { 2 2. query Collection 1 for product id to retrieve ID. The results of the query in step 2 sometimes returns the id and sometimes return undefined. but the output was actually 'undefined' Solution 1: .find () requires the function to return a truthy value when the condition is matched. Here is my API endpoint: sendRequest async function that returns undefined async function sendRequest (url) { let code; request ( { url, timeout: 20000 }, function (error, response, body) { if (error == 'ENOTFOUND' || error == 'ETIMEDOUT') { response.statusCode = 500; } code = response.statusCode return { code, error } }); } javascript node.js async-await Share You are not waiting to get the promise fulfilled. Helpful resources. React Native Await Async does not return value before alerting user and setting state; returning an async value is returning "undefined" - why can't I return a value? Right now, I am getting undefined as the return value of openChat and can't work out why. Skip to content return asynchronous result and not undefined. Async function returning undefined . pass a callback funcion into an async function node js. Try it Syntax When that promise is fulfilled after the return, you are seeing the output in the console. The return value from a Asynchronous Xrm.WebApi is. Your function doesn't return anything, it just splices the element out, so find () never returns the matching element. javascript by Ham-Solo on Jan 29 2021 Donate Comment . The async and await keywords enable asynchronous, promise-based behavior to be written in a cleaner style, avoiding the need to explicitly configure promise chains. async function in variable. You're not returning from your async function so the value implied is going to be undefined. return response.results [0].elevation } but that returns from that function, not the parent async function its in. 3. save input fields to Collection 2 including ID (retrieved in step 2) to create the reference link between collection 1 & 2. with return countQuery.then (.). Your estimation () function returns undefined instead of returning a promise, that is because you return the new string from the callback function. Search Loose Match Exact Match. Expected results are a returned string. The function otherwise works, apart from the return. But an async function returns a Promise, which can't be called as a function! Where it always returns promise pending, but in the results I can see the value. It's simply not what the useEffect hook expects for its first argument. 1 Code Answers . . .then (async. The function is to create the chat/find existing chat, and return its ID. So, I have changed the function to . But you are right about #2. javascript async await not waiting. Actual results are that the return value of the async function is undefined. The callback of onMessage should return a literal true value (documentation) in order to keep the internal messaging channel open so that sendResponse can work asynchronously.. replace countQuery.then (.) The issue here is that the first argument of useEffect is supposed to be a function that returns either nothing ( undefined) or a function (to clean up side effects). "async function returns undefined" Code Answer. Async wraps the whole thing in a new promise, he can use the callback like that. Array.prototype.map() expects a return value from arrow function array-callback-return; await not waiting for async function to return value; How to get the return value of a async function that returns a promise; Should I return true to clear .map() expects a value to be returned at the end of arrow function warning? 1 People found this is helpful async-await javascript node.js Advertisement Share Improve this answer Follow edited Oct 7, 2018 at 15:24 IftekharDani 3,504 1 15 18 answered Oct 7, 2018 at 13:49 orpris12 156 3 You have to write: replace countQuery.then (.) Problem. I'm not sure if I'm doing this right but every async function I use keeps on returning null. Your estimation () function returns undefined instead of returning a promise, that is because you return the new string from the callback function. with return countQuery.then (.). In the example below, erpBaseUrl within the newOrder function returns undefined, whilst console.log(url) within the getEnvironment function returns a value. SBX - Heading. Sort: Best Match . Try with await and return your return after the promise is fulfilled Your callback is declared with async keyword, so it returns a Promise, not a literal true value.Chrome extensions API doesn't support Promise in the returned value of onMessage callback until https://crbug.com . @jfriend00 explained the problem - here's one possible solution that uses Node.js's util.promisify function to take the db_office.query function and turn it into something that can actually be awaited upon.. "Undefined" return value from async function I have a async function as follows: // Checking if the user is in database or not, if not, add async function userHandler(username, displayName, profilePicture, email) { connection = await connectDB() await connection.query('USE spyncdb;'); SBX - Ask Questions. An async function is a function declared with the async keyword, and the await keyword is permitted within it. Here is my sample code: var bcrypt = require('bcryptjs'); var password . You are returning from the request callback: response => { // . Please heed the comments in the code. Async functions may also be defined as expressions. Why can't I get the value of url? I have two functions. 1. save input fields to Collection 1. So, just after running the function, that promise is getting added in the asynchronous event loop and returned. 1 Source: . 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